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For the reaction, calculate how many moles of the product form when 2.05 mol of O2 completely reacts.
Assume that there is more than enough of the other reactant.
2H2(g)+O2(g)→2H2O(l)

Respuesta :

Answer:

n H2O(l) = 4.1 mol

Explanation:

  • 2H2(g) + O2(g) → 2H2O(l)

∴ n O2(g) = 2.05 mol

⇒ n H2O(l) = ( 2.05 mol O2 )×( 2 mol H2O / mol O2 )

⇒ n H2O(l) = 4.1 mol

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