Answer:
Sn is independent of b
Step-by-step explanation:
t1=a-b
tn=a+b
we know that nth term of arithmetic series is an=a1+(n-1)d
so
a+b=a-b+(n-1)d
⇒2b=(n-1)d-----------equation 1
formula for sum of n terms of arithmetic series
Sn=[tex]\frac{n}{2}[/tex](2a1+(n-1)d)
⇒Sn=[tex]\frac{n}{2}[/tex](2(a-b)+2b) (since (n-1)d=2b from equation 1)
⇒Sn=[tex]\frac{n}{2}[/tex](2a)
therefore we can see that Sn is independent of b
