The required value of the given expression is [tex]\frac{81}{x^{128}y^{10}}[/tex]
The given expression is,
[tex](3x^3y^0 x^{-2})^4 \times(y^2x^{-45}xy^{-8})^3[/tex]
Simplifying the given expression as
[tex](3x^3y^0 x^{-2})^4 \times(y^2x^{-45}xy^{-8})^3=(3^4\times x^{12}y^0x^{-8})(y^6x^{-135}x^3y^{-24})\\=81x^4y^8(y^6x^{-135}x^3y^{-24})\\=\frac{81x^4y^8\times1}{x^{132}y^{18}} \\=81(\frac{x^4}{x^{132} })(\frac{y^8}{y^{18}})\\ =\frac{81}{x^{128}y^{10}}[/tex]
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