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The half-life of sodium-22 is 2.6 years. A sample contains 800 mg of this isotope.

Which expression represents the mass of sodium remaining after h half-lives?

S = 0.5(800)h

S = 800(0.5)h

S = 8000.5h

S = 800h + 0.5
Which expression relates h, the number of half-lives, and y, the number of years?

Respuesta :

Answer:

The answer is B S=800(0.5)h

Which expression relates h, the number of half-lives, and y, the number of years? Answer h=y/2.6

Combine the first two equations and laws of exponents to find the equation for the mass of sodium remaining after y years. Answer S=800(0.766)y

Approximately how many milligrams of sodium remain after 8.4 years? Answer 85.2 mg

Step-by-step explanation:

The exponential function that represents the mass of sodium remaining after h half-lives is given by:

[tex]S(t) = 800(0.5)^h[/tex]

What is an exponential function?

A decaying exponential function is modeled by:

[tex]A(t) = A(0)(1 - r)^t[/tex]

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.
  • t is the period.

Half-life is the time for the amount to be half of it is, hence t = h, r = 0.5. The initial amount is of A(0) = 800 mg, hence, the equation is:

[tex]S(t) = 800(0.5)^h[/tex]

More can be learned about exponential functions at https://brainly.com/question/25537936