Answer:
(D) p = 50.55 (Round to the nearest hundredth).
Step-by-step explanation:
Given: Right triangle SIP such that i = 54 and s = 19.
To find: Which of the following statements are true, round to the nearest hundredth.
Solution: We have given that Right triangle SIP , i = 54 and s = 19.
By the Pythagoras theorem (IP)²+(SI)² = (SP)².
Plugging the values
(19)²+(p)² = (54)².
361+(p)² =2916
On subtracting both side by 361.
(p)²+ 361 - 361 =2916 -361
(p)² = 2555
Taking square root both sides .
√(p)² = [tex]\sqrt{2555}[/tex].
p = 50.547
p = 50.55 (Round to the nearest hundredth).
Therefore, (D) p = 50.55 (Round to the nearest hundredth).
