Respuesta :

r3t40

We have [tex]f(n)=f(n-1)+5.5[/tex]. By entering 3 we get [tex]f(3)=f(3-1)+5.5=f(2)+5.5[/tex] because we enter again the function will apply further (will be recursive). [tex]f(2)=f(2-1)+5.5+5.5=f(1)+5.5+5.5=3+5.5+5.5=\boxed{14}[/tex].

Hope this helps.

MathPhys

Answer:

14

Step-by-step explanation:

Plug in 3 in f(n).

f(3) = f(3−1) + 5.5

f(3) = f(2) + 5.5

We need to find f(2).  So plug in 2 in f(n).

f(2) = f(2−1) + 5.5

f(2) = f(1) + 5.5

f(2) = 3 + 5.5

f(2) = 8.5

Therefore:

f(3) = 8.5 + 5.5

f(3) = 14