Answer:
Rate of the passenger train is [tex]48\ mph[/tex] and the rate of the freight train is [tex]32\ mph[/tex]
Step-by-step explanation:
Let the speed of the passenger train be [tex]x\ mph[/tex]
Speed of the freight train be [tex](x-16)\ mph[/tex]
Note:
If the passenger train overtakes the freight train than at the point both have traveled same distance as they are from the same station.
And [tex]Distance=Speed\times time[/tex]
Time taken by the passenger train to reach that point [tex]=2\ hrs[/tex]
Time taken by freight train,= (time taken by the passenger train + time elapsed) [tex]=(2+1)=3\ hrs[/tex]
Re-arranging the terms.
Distances are same.
[tex]3(x-16)=2(x)[/tex]
[tex]3x-48=2x[/tex]
Subtracting [tex]2x[/tex] both sides.
[tex]3x-2x=48[/tex]
[tex]x=48\ mph[/tex]
So the rate of the passenger train is [tex]x\ mph=48\ mph[/tex] and the rate of the freight train is [tex](x-160)\ mph =(48-16)=32\ mph[/tex]