Find the area of a regular hexagon with the given measurement. 4-inch side A = sq. in. Please show work.
Answer:
[tex]A=41.57 inch^2[/tex]
Step-by-step explanation:
Given.
The side of regular hexagon is 4-inch
Find the Area of regular hexagon?
The Area of regular hexagon is
[tex]A=\frac{3\sqrt{3} }{2}\times (sides)^{2}[/tex]
[tex]A=\frac{3\sqrt{3} }{2}\times (4)^{2}[/tex]
[tex]A=\frac{3\sqrt{3} }{2}\times 16[/tex]
[tex]A=3\times 8\times \sqrt{3}[/tex]
[tex]A=24\sqrt{3}[/tex]
[tex]A=41.57[/tex]
Therefore, the area of regular hexagon is [tex]A=41.57 inch^2[/tex].
