How many milliliters of a 10.6 M NaOH solution are needed to prepare 0.715 L solution of NaOH with a concentration of 0.550 M?

Respuesta :

Answer:

37.1mL

Explanation:

This is a simple dilution problem where you utilize the equation:

(C=Concentration, V=Volume)

C1V1=C2V2

10.6(y)=0.715x0.550 (Y is unknown because we are trying to find how much of the original solution we need to dilute to make the final solution)

The solve for y and you get

y= 0.0317 L but this is in L and we want mL so multiply by 1000 you get

y= 37.1mL

The required volume of 10.6 M NaOH solution is 0.0317 L and the further calculation can be defined as follows:

Given that:

Molarity of concentrated NaOH solution = 10.6 M

Molarity of diluted NaOH solution = 0.550 M

Volume of diluted NaOH solution = 0.715 L

To find:

Volume of stock solution required.

Formula used to calculate the volume of stock solution is:

[tex]C_1V_1=C_2V_2[/tex]

where, [tex]C_1\text{ and }V_1[/tex] are the concentration and volume of stock solution and [tex]C_2\text{ and }V_2[/tex] are the concentration and volume of diluted solution.

Put the values in the above formula:

[tex]10.6\times V_1=0.550\times 0.715\\\\V_1=\frac{0.550\times 0.715}{10.6}\\\\V_1=0.0371L[/tex]

So, the required volume of 10.6 M NaOH solution is 0.0371 L.

Learn more about dilution law: https://brainly.com/question/13927454