Answer:
10
Step-by-step explanation:
To find the duration that corresponds to a descent by 505050 meters, we need to find the relationship's rate of change. In linear relationships, the rate of change is represented by the slope of the line. We can calculate this slope from any two points on the line.
Two points whose coordinates are clearly visible from the graph are (100,8000) and (200,7500)
Now, to find the slope, let's take the ratio of the corresponding differences in the y-values and the x-values:
{7500-8000}{200-100}={-500}{100}=-5
200−100
7500−8000 = 100−500 =−5
Start fraction, 7500, minus, 8000, divided by, 200, minus, 100, end fraction, equals, start fraction, minus, 500, divided by, 100, end fraction, equals, minus, 5
The slope of the line is -5−5minus, 5, which means the rate of change is 5 meters per second. So the plane descended 50 meters every {50}{5}=10
50/5=10
10 seconds
