Answer:
E = 3.1885 E16 J
Explanation:
∴ c = 3 E8 m/s
∴ m = (2.53 E1)(14.003241 amu) = 354.282 g isotope
⇒ E = (354.282 g)(3 E8)²
⇒ E = 3.1885 E19 g.m²/s²
⇒ E = 3.1885 E16 Kg.m²/s² = 3.1885 E16 J
Answer : The amount of energy released is, [tex]3.189\times 10^{16}J[/tex]
Explanation :
Formula used to calculate the amount of energy released is:
[tex]E=mc^2[/tex]
where,
E = amount of energy released
m = mass of isotope
c = speed of light = [tex]3\times 10^8m/s[/tex]
First we have to calculate the mass of isotope.
Mass of isotope = Moles of isotope × Atomic mass of isotope
Mass of isotope = (2.530 × 10)mol × 14.003241 amu
Mass of isotope = 354.3 g = 0.3543 kg
Now we have to calculate the amount of energy released.
[tex]E=mc^2[/tex]
[tex]E=(0.3543kg)\times (3\times 10^8m/s)^2[/tex]
[tex]E=3.189\times 10^{16}J[/tex]
Thus, the amount of energy released is, [tex]3.189\times 10^{16}J[/tex]
