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The center of a 910 kg satellite is 9.9x10^6 m from the earths center.What is the gravitational force between the satellite and earth? What addition information is required to solve this problem

Respuesta :

Answer:

3678.33 N , Earth weight has to be given

Explanation:

F = (G x m1 x m2) / r²

F is  gravitational force between the satellite and earth

G is Gravitational contant  which is 6.674x10^(-11) Nm² / kg²

m1 is earth weight (5936x 10^(24) )

m2 is satellite weight

r is distance between earth and satellite

So , F is ;

= [6.674 x 10^(-11) x 5936 x 10^(24) x 910 ] / (9.9 x 10^6)²

= 3678.33 N

The law of universal gravitation allows to find the answer for the  force between the earth and the satellite is:

     a) F = -3.68 10³ N

     b) To solve the problem the mass of the Earth is required.

The law of universal gravitation stable that the gravitational force between bodies is attractive and is given by the expression.

           [tex]F = - G \frac{Mm}{r^2 }[/tex]  

Where F is the force, G is the universal gravitational constant that is equal to G = 6.67 10⁻¹¹ Nm²/kg, M and m are the mass of the bodies and r the distance between them.

They indicate the mass of the satellite is m = 910 kg and the distance from the satellite to the earth r = 9.9 10⁶ m.

The data of the mass of the Earth that is tabulated is missing and is worth M = 5.98 10²⁴ kg

Let's calculate.

              [tex]F = - 6.67 \ 10^{-11} \ \frac{910 \ 5.98 \ 10^{24} }{(9.9 \ 10^6 )^2 }[/tex]  

              F = - 3.68 10³ N

The negative sign indicates that the force is attractive.

In conclusion using the law of universal gravitation we can find the answer for the  force between the earth and the satellite is:

     a) F = -3.68 10³ N

     b) To solve the problem the mass of the Earth is required.

Learn more of the law of universal gravitation here:  brainly.com/question/858421