Answer:
The skydiver will fall 1600 ft in 10 seconds.
Step-by-step explanation:
Distance a body falls from rest varies directly as the squares of the time it falls
Let distance = s
time = t
Therefore , s = k [tex] \times t^{2}[/tex]
Given, the body falls 64 ft in 2 seconds.
Substituting in above equation,
64 = k [tex] \times (2)^{2}[/tex]
64 = k [tex] \times (4) [/tex]
k = [tex]\frac{64}{4}[/tex]
k = 16 ft/[tex]s^{2}[/tex]
We have to find how much he will fall in 10 seconds.
s = k [tex] \times t^{2}[/tex]
s = [tex]16 \times 10^{2}[/tex]
s = [tex]16 \times 100[/tex]
s = 1600 ft
