Answer:
8 litres of the 20% and
7 litres of the 50% solution.
Step-by-step explanation:
Let the number of litres be x for 20% and y for the 50% solution. Then
0.2x + 0.5y = 15*0.34
0.2x + 0.5y = 5.1 Also we have:
x + y = 15 Multiply the first equation by -2:
-0.4x - y = -10.2 Adding these last 2 equations:
0.6x = 4.8
x = 4.8 / 0.6
x = 8.
and y = 15 - 8 = 7 .
This question is based on the system of equation. Therefore, the 8 litres of the 20% and 7 liters of the 50% solution.
Given:
A chemist needs to mix an 20% acid solution with a 50% acid solution to obtain 15 liters of a 34% acid solution.
We need to determined the numbers of liters of each of the acid solutions must be used.
According to the question,
Let the number of liters be x for 20% and y for the 50% solution.
Then,
⇒ 0.2x + 0.5y = 15 [tex]\times[/tex] 0.34
⇒ 0.2x + 0.5y = 5.1
Also we have:
Multiply the first equation by -2:
⇒ x + y = 15
Adding these last 2 equations:
⇒ -0.4x - y = -10.2
⇒ 0.6x = 4.8
⇒ x = 4.8 / 0.6
⇒ x = 8 and y = 15 - 8 = 7 .
Therefore, the 8 liters of the 20% and 7 liters of the 50% solution acid solutions must be used.
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https://brainly.com/question/25147706
