Answer:
Empirical Probability that a family's first child will be born with this syndrome is 0.0002.
Step-by-step explanation:
Empirical Probability of an event E is defined
[tex]\textrm{P(E)} = \frac{\textrm{Number of times the event actually happens}}{\textrm{ Total number of times the experiment performed }}[/tex]
Let E: Event that the child born has a certain syndrome.
Now here, total number of times experiments performed = 50,000
The number of favorable outcome = 1
[tex]\implies P(E) = \frac{1}{50,00} = 0.0002[/tex]
Hence, here the Empirical Probability that a family's first child will be born with this syndrome is 0.0002.
