Answer:
The net ionic equation:
[tex]Ca^{2+}(aq)+CO_{3}^{2-}(aq) \rightarrow CaCO_{3}(s)[/tex]
Explanation:
The given chemical reaction is as follows.
[tex](NH_{4})_{2}CO_{3}(aq)+Ca(ClO_{4})_{2}(aq) \rightarrow CaCO_{3}(s)+2NH_{4}ClO_{4}(aq)[/tex]
The total ionic equation is as follows.
[tex]2NH_{4}^{+}(aq)+ CO_{3}^{2-}(aq)+Ca^{2+}(aq)+2ClO_{4}^{-}(aq) \rightarrow CaCO_{3}(s)+2NH_{4}^{+}(aq)+2ClO_{4}^{-}[/tex]
Similar ions on the both sides of the reaction will be cancelled.
The remaining reaction is
[tex]Ca^{2+}(aq)+CO_{3}^{2-}(aq) \rightarrow CaCO_{3}(s)[/tex]
Therefore, the net ionic reaction is as follows.
[tex]Ca^{2+}(aq)+CO_{3}^{2-}(aq) \rightarrow CaCO_{3}(s)[/tex]
