Answer:
The graph of the system in the attached figure
Step-by-step explanation:
we have
[tex]x^{2}+y=2[/tex]
isolate the variable y
[tex]y=-x^{2}+2[/tex] ----> equation A
This is the equation of a vertical parabola open down (because the leading coefficient is negative)
The vertex represent a maximum
the vertex is the point (0,2)
[tex]x^{2} +y^{2}=9[/tex] ---> equation B
This is the equation of a circle centered at (0,0) with radius 3 units
The solution of the system of equations is the intersection points both graphs
using a graphing tool
The solutions are the points (-2.05,-2.19) and (2.05,-2.19)
see the attached figure
