Answer:
The second pyramid, placed in the middle, has a volume of 15 square units.
Step-by-step explanation:
Givens
- The area of the bases is 15 square units.
- All of them have the same base.
The volum of a pyramid is defined as
[tex]V=\frac{1}{3}Bh[/tex]
Where[tex]B[/tex] is the are of the base and [tex]h[/tex] is the height.
So, all of them have [tex]B=15u^{2}[/tex]
The first pyramid has a height of 4, replacing this in the formula we have
[tex]V=\frac{1}{3}15(4)=5(4)=20u^{3}[/tex]
The second pyramid has a height of 3
[tex]V=\frac{1}{3}15(3)=5(3)=15u^{3}[/tex]
The third pyramid has a height of 12
[tex]V=\frac{1}{3}15(12)=5(12)=60u^{3}[/tex]
Therefore, the second pyramid, placed in the middle, has a volume of 15 square units.
