The top and bottom margins of a poster are 6 ft and the side margins are each 8 ft. If the area of printed material on the poster is fixed at 386 square ft, find the dimensions of the poster with the smallest area.

Respuesta :

Answer:

Dimension

Height =29.01

Breadth=38.70

Step-by-step explanation:

Printed area is =386 and margins as specified.

For printed area let height be x and breadth be y.

x*y=386 ⇒ y = [tex]\frac{386}{x}[/tex]

Now considering the margins

Height = x+6+6=x+12

Weidth = [tex]\frac{386}{x}[/tex] +8 +8= [tex]\frac{386}{x}[/tex] + 16

Area of poster to be minimised =(x+12)([tex]\frac{386}{x}[/tex] + 16)

Differentiate above area with respect to x and equate to zero to find extrema.

 [tex]\frac{dA}{dx}[/tex] = 16 -[tex]\frac{12*386}{x^{2} }[/tex]=0

x=17.01

Now plug value of x in height and breadth

 Height =29.01

Breadth=38.70

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