The unknown substance can be lithium, which has a specific heat capacity of approximately [tex]3.5 J/gK[/tex].
Explanation:
When heat energy is supplied to a certain substance, the temperature of the substance increases according to the equation:
[tex]Q=mC_s \Delta T[/tex]
where
Q is the amount of energy supplied
m is the mass of the sample
[tex]C_s[/tex] is the specific heat capacity of the substance
[tex]\Delta T[/tex] is the change in temperature
In this problem, we have
m = 4.9 g is the mass
Q = 668.85 J is the specific heat capacity
[tex]\Delta T = 39 K[/tex] is the change in temperature
Solving for [tex]C_s[/tex], we find the specific heat capacity of the substance:
[tex]C_s = \frac{Q}{m\Delta T}=\frac{668.85}{(4.9)(39)}=3.5 J/gK[/tex]
Looking at tables of specific heat capacity, we can see that the unknown substance can be lithium, which has a specific heat capacity of approximately [tex]3.5 J/gK[/tex].
Learn more about specific heat capacity:
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