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A sample of gas at 181.8 ◦C has a volume of 4.34 L. The volume expands to 10.44 L due to a temperature change at constant pressure. What will be the new temperature(in degrees Celcius)? (round your answer to the hundredth place)

Respuesta :

Answer:

Final temperature = 821.25 °C

Explanation:

In this process, we expand a gas at constant pressure from one temperature to another temperature.

According to Avogadro's law , ratio of volume and temperature for an ideal gas remains constant .

  • [tex]V_{1} = 4.34 L[/tex]
  • [tex]V_{2} = 10.44 L[/tex]
  • [tex]T_{1} = 454.95 K[/tex]
  • [tex]T_{2} = [/tex] unknown

[tex]\frac{V}{T}[/tex] = constant

[tex]\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }[/tex]

[tex]\frac{4.34}{454.95} = \frac{10.44}{T_{2} }[/tex]

[tex]T_{2} = [/tex] 1094.4 K

To convert the temperature to celsius, subtract 273.15 from final temperature in K.

So , [tex]T_{2} = [/tex] 821.25 °C