Answer:
13.84 L of Ne gas
Explanation:
The exercise can be resolved by applying the General Gas Law, which establishes the relationship between the Pressure, Volume and Temperature of a gas in its initial state and its final state. Mathematically, it is:
[tex]\frac{P1 x V1}{T1} = \frac{P2 x V2}{T2}[/tex]
To use this equation, you need to convert the temperatures from Celsius scale to Kelvin scale (absolute scale), and to make this conversion the formula is used:
T (K) = t (° C) + 273.15
We replace the values and obtain the absolute temperatures of the initial state (T₁) and the final state (T₂)
T₁ (K) = 27.0 ° C + 273.15 = 300.15 K
T₂ (k) = 77.0 ° C + 273.15 = 350.15 K
Clearing in the equation of the general gas law V₂, and replacing the other values provided by the statement, the equation and result would be:
[tex]V2 = \frac{P1 x V1 x T2}{T1 x P2} = \frac{1.20atm x 35.6L x 350.5K}{300.15K x 3.60 atm} = 13.84L[/tex]
Therefore, the final volume occupied by the gas sample Ne is 13.84 L
