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The center of circle is: (-7,4) and Radius is 7 units

Step-by-step explanation:

We have to compare the given equation of circle with standard equation of circle

Given equation is:

[tex](x+7)^2 + (y-4)^2 = 49[/tex]

Standard equation of circle is:

[tex](x-h)^2+(y-k)^2 = r^2[/tex]

Here

h and k are coordinates of center of circle

So,

comparing

[tex]x- h = x + 7\\-h = 7\\h = -7\\and\\y - k = y - 4 \\k = 4\\and\\r^2 = 49\\\sqrt{r^2} = \sqrt{49}\\r = 7[/tex]

Hence,

The center of circle is: (-7,4) and Radius is 7 units

Keywords: Circle, radius

Learn more about circle at:

  • brainly.com/question/1284310
  • brainly.com/question/1279756

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Answer:

[tex]\displaystyle 7 = R \\ (-7, 4)[/tex]

Explanation:

[tex]\displaystyle (X - H)^2 + (Y - K)^2 = R^2[/tex]

In this circle equation, all the negative symbols give you the OPPOSITE TERMS OF WHAT THEY REALLY ARE, so first off, taking the square root 49 will give you a radius of 7 units, and the centre of the circle will be [tex]\displaystyle (-7, 4).[/tex]

* [tex]\displaystyle (h, k) → centre\:of\:a\:circle[/tex]

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