Answer:
The [tex][OH^{-}][/tex] is [tex]2\times10^{-11}[/tex]
Explanation:
Number of moles of HBr= [tex]6.00\times 10^{-3}[/tex]
Volume of water = 12.0 L
[tex][HBr]= \frac{6.00\times 10^{-3}}{12}M[/tex]
[tex][H^{+}]= \frac{6.00\times 10^{-3}}{12}M[/tex]
[tex][H^{+}][OH^{-}]= 10^{-14}[/tex]
[tex][OH^{-}]= \frac{1.0\times 10^{-14}}{[\frac{6 \times10^{-3}}{12}]}= \frac{12 \times 10^{-14}}{6 \times10^{-3}}=2\times10^{-11}[/tex]
Therefore, [tex][OH^{-}][/tex] is [tex]2\times10^{-11}[/tex].
