The co-ordinates of point R is (6 , 2)
Solution:
Given that M(7, 3) is the midpoint of RS
Also co-ordinates of point S is (8, 4)
To find: co-ordinates of point R
The midpoint of two points [tex]P(x_1, y_1)[/tex] and [tex]Q(x_2, y_2)[/tex] is given as:
[tex]M=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)[/tex]
Here midpoint M = (7, 3) and point S [tex](x_1 , y_1) = (8, 4)[/tex]
Point R = [tex](x_2, y_2)[/tex]
Substituting the values in formula we get,
[tex](7,3)=\left(\frac{8+x_{2}}{2}, \frac{4+y_{2}}{2}\right)[/tex]
Comparing both the sides we get,
[tex]\frac{8+x_{2}}{2}=7[/tex] and [tex]\frac{4+y_{2}}{2}=3[/tex]
On solving,
[tex]\begin{array}{l}{14=8+x_{2}} \\\\ {x_{2}=6}\end{array}[/tex]
Also,
[tex]\begin{array}{l}{4+y_{2}=6} \\\\ {y_{2}=2}\end{array}[/tex]
Thus the co-ordinates of point R is (6 , 2)
