Answer:
Adrian would have to purchase 9 cans and 3 frozen dinners.
step-by-step explanation:
Let us consider the sodium is denoted by a variable "s"
Let us consider the can is denoted by a variable "c"
Each can of soup containing the sodium = s = 350 mg
Each frozen dinner containing the sodium = s = 700 mg
The number of cans purchased by Adrian = c = 9 cans
The total amount of sodium = 5250 mg
Total amount of sodium purchased by Adrian
in 9 cans = 9 × 35 = 3150 mg
Subtracting 5250 mg by 3150 mg will give 2100 mg
So, 5250 mg - 3150 mg = 2100 mg
Dividing 2100 mg by 700 mg of sodium of frozen sodium will give the value 3.
So, Adrian would have to purchase 3 frozen dinner.
Hence, Adrian would have to purchase 9 cans and 3 frozen dinners to collectively contain 5250 mg of sodium.
Verification:
The total amount of sodium = 5250 mg
Total amount of sodium purchased by Adrian in 9
cans = 9 × 350 = 3150 mg
Total amount of sodium purchased by Adrian in 3 frozen dinners = 3 × 700 = 2100 mg
Total sodium = sodium purchased in cans + sodium purchased in frozen dinners
5250 = 3150 + 2100
5250 = 5250
L.HS = R.HS
Keywords: system of equation, word problem, variables
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