Respuesta :
Answer:
The revenue is maximum around 187.5 that means we can sell 187 or 188 calculators to get the maximum revenue.
Step-by-step explanation:
Let the total number of calculators sold = x
The price per demand of calculator , p =150 - 0.4x
Total revenue =[tex] number of calculators sold \times price of each [/tex]
= [tex] x \times (150 - 0.4x) [/tex]
To maximize revenue, derivative of total revenue must be zero.
[tex]\frac{d}{dx} x(150 - 0.4x)[/tex] = 0
150 - 0.4x - 0.4x = 0
150 - 0.8x = 0
0.8x = 150
x = 187.5
So the revenue is maximum around 187.5 that means we can sell 187 or 188 calculators to get the maximum revenue.
Maximum revenue = [tex] 188 \times (150 - 0.4 \times 188)[/tex]
=14,062.4
