Answer:
The length of the flag is 730 ft and the width is 310 ft
Step-by-step explanation:
The correct question is
The perimeter of the flag is 2080 ft what is the flags width and length if the length is 420 ft greater than the width
Let
L ----> the length of the flag
W ---> the width of the flag
we know that
The perimeter of the flag (rectangle) is equal to
[tex]P=2(L+W)[/tex]
we have
[tex]P=2,080\ ft[/tex]
so
[tex]2,080=2(L+W)[/tex]
[tex]1,040=L+W[/tex] ----> equation A
[tex]L=W+420[/tex] ---> equation B
Solve the system by substitution
substitute equation B in equation A
[tex]1,040=(W+420)+W[/tex]
solve for W
[tex]1,040=2W+420[/tex]
[tex]2W=1,040-420[/tex]
[tex]2W=620[/tex]
[tex]W=310\ ft[/tex]
Find the value of L
[tex]L=W+420[/tex] ----> [tex]L=310+420=730\ ft[/tex]
therefore
The length of the flag is 730 ft and the width is 310 ft
