Answer:
162.5 m is the distance traveled by an object.
Explanation:
Given that,
An object's constant acceleration (a) is [tex]13m/s^2[/tex].
The time (t) it traveled is 5 seconds.
The object is at rest that is "initial velocity" (u) is 0 m/s.
To find the distance traveled use the below formula,
[tex]s=ut+\frac{1}{2}at^2[/tex]
Where, "s" is distance traveled, "u" is initial velocity, "a" is acceleration and "t" is time taken.
Substitute the given values in the above formula,
[tex]s=0\times5+\frac{1}{2}\times13\times 5^2[/tex]
[tex]s=0+\frac{1}{2}\times13\times 25[/tex]
[tex]s=0+\frac{1}{2}\times325[/tex]
s = 162.5 m
Therefore, distance traveled is 162.5 m.
