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If it takes three "breathes" to blow up a balloon to 1.2 L, and each breath supplies the balloon with 0.060 moles of exhaled air, how many moles of air are in a 3.0 L balloon?

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masonrpalomo
a 3.0 L balloon is 2.5 times as big as a 1.2L balloon, and 3 times .060 equals .18, so if you multiply .18 by 2.5 you get .45 moles of air i’m pretty sure
okpalawalter8

The moles of air are in a 3.0 L balloon are mathematically given as

x=0.45m

What moles of air are in a 3.0 L balloon?

Question Parameter(s):

If it takes three "breathes" to blow up a balloon to 1.2 L

the balloon with 0.060 moles of exhaled air

Generally, the size of the balloon  is mathematically given as

v=1.2*2.5

v=3.0L

Therefore

v'=3*0.06

v=0.18

In conclusion, moles of air are in a 3.0 L balloon is

x=v'*2.5

x=0.18*2.5

x=0.45m

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