Respuesta :
Answer:
That is the solutions are:
[tex]\frac{\pi}{3}+2\pi \cdot k[/tex],[tex]\frac{5\pi}{3}+2\pi \cdot k[/tex]
Step-by-step explanation:
The period of [tex]\cos(x)[/tex] or [tex]\sin(x)[/tex] is [tex]2\pi[/tex].
Let's look at the first rotation to see when [tex]\cos(\theta)=\frac{1}{2}[/tex] happens.
This happens at [tex]\frac{\pi}{3}[/tex] and also at [tex]\frac{5\pi}{3}[/tex]. (Notice I just looked at the x-coordinates because that is what cosine is. Sine is the y-coordinate.)
Now to find the rest of the solutions we can just make full rotations either way to get back to those points .
That is the solutions are:
[tex]\frac{\pi}{3}+2\pi \cdot k[/tex]
[tex]\frac{5\pi}{3}+2\pi \cdot k[/tex]
