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One night a theater sold 548 movie tickets. Adults ticket cost $6.50 and a child’s ticket cost $3.50. In all, $2881 was taken in. How many of each kind of ticket were sold?

Respuesta :

Teryyy

Answer:

321 adults and 227 ninos (children)

abidemiokin

227 children tickets and 321 adults tickets were sold

  • Let the amount of child's ticket be x

  • Let the amount of adults tickets be y

If the total tickets sold is 548 movie tickets, then;

x + y  = 548

  • x = 548 - y ..........................1

If adult ticket cost $6.50 and a child’s ticket cost $3.5 with a total of $2881 in all, then;

3.5x +  6.5 y = 2881

  • 35x + 65y = 28810 ...................2

Substitute equation 1 into 2:

35x + 65y = 2881

35(548-y) + 65y = 28810

19180 - 35y + 65y = 28810

30y = 28810 - 19180

30y = 9630

y = 9630/30

y = 321

Recall that x = 548 - y

x = 548 - 321

x = 227

Hence 227 children tickets and 321 adults tickets were sold

Learn more on simultaneous equations here:

https://brainly.com/question/6597041

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