Respuesta :
Answer:
41.7 g of Zinc Chloride are produced when 20.0 g of Zinc reacts with excess Hydrochloric acid.
Explanation:
The balanced equation for the reaction is:
[tex]Zn+2HCl\longrightarrow ZnCl_{2}+H_{2}\\65.4g\:of\:Zn\:gives\:136.4g\:of\:ZnCl_{2}\\\\20.0g\:of\:Zn\:gives=\frac{136.4\times20}{65.4}=41.7g\:of\:ZnCl_{2}[/tex]
41.7 g of Zinc Chloride are produced when 20.0 g of Zinc reacts with excess Hydrochloric acid.
The moles of product and reactant in the chemical equation are given by the stoichiometric coefficient. The grams of zinc chloride produced in the reaction is 41.57 grams.
What is stoichiometric law?
The stoichiometric law gives the idea about the moles of reactant and product in the reaction have been equivalent to the stoichiometric coefficient.
The reaction of zinc chloride is given as:
[tex]\rm Zn\;+\;2\;HCl\;\rightarrow\;ZnCl_2\;+\;H_2[/tex]
The mass in terms of moles is given as:
[tex]\rm Moles\;=\dfrac{Mass}{Molar\;mass}[/tex]
The molar mass of zinc is 65.38 g/mol, and zinc chloride is 136.286 g/mol.
According to the stoichiometric law, the mass of zinc chloride formed is:
[tex]\rm 1\;mol\;Zn=1\;mol\;ZnCl\\\\\dfrac{20\;g}{65.38\;g/mol} \;Zn=\dfrac{20\;g}{65.38\;g/mol} \;\times\;{136.286\;\;g/mol} \;ZnCl\\\\0.305\;mol\;Zn=41.57\;g\;ZnCl[/tex]
The mass of ZnCl formed with 20 g Zn is 41.57 grams.
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