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What is the pressure inside a cylinder when the volume changes from 12.49 dm3 to 47.32 dm3 with an initial pressure of 7.257 x 102 kPa? The temperature of the cylinder remained constant at 37.1ºC

Respuesta :

Answer:

The pressure inside becomes : 202.646 KPa

Explanation:

Given ,

  • The temperature inside the cylinder is constant
  • The number of moles of the gas inside the cylinder will also be constant because it's a closed one.

Now according Boyle's law ,

  • The pressure of a gas of fixed mass is inversely proportional to its volume at a constant temperature.

Thus ,

[tex]P_1V_1=P_2V_2\\[/tex]

  • [tex]P_1[/tex] is the initial pressure [tex]7.257*102*10^3 Pa[/tex]
  • [tex]P_2[/tex] is what we need to find
  • [tex]V_1 = 12.49dm^3[/tex] - initial volume
  • [tex]V_2 = 47.32dm^3[/tex] - final volume

∴

[tex]7.527*102*10^3*12.49=P_2*47.32\\P_2=2.02646*10^5Pa[/tex]

The pressure inside becomes : 202.646 KPa

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