A beam of light passes through a liquid into air. Angle 1, angle of
incidence, is 23°. The angle 2, angle of refraction is 38°. Refractive
index for air is 1.00. Calculate the refractive index of the liquid
medium.

Respuesta :

Answer: 1.57

Explanation:

This described situation is known as Refraction, a phenomenon in which light bends or changes its direction when passing through a medium with a index of refraction different from the other medium.  

In this context, the index of refraction is a number that describes how fast light propagates through a medium or material.  

According to Snell’s Law:  

[tex]n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})[/tex] (1)  

Where:  

[tex]n_{1}[/tex] is the first medium index of refraction (the value we want to know)

[tex]n_{2}=1[/tex] is the second medium index of refraction (air)  

[tex]\theta_{1}=23\°[/tex] is the angle of incidence

[tex]\theta_{2}=38\°[/tex] is the angle of refraction

Now, let's find [tex]n_{1}[/tex] from (1):

[tex]n_{1}=n_{2}\frac{sin \theta_{2}}{sin \theta_{1}}[/tex] (2)  

Substituting the known values:

[tex]n_{1}=1\frac{sin(38\°)}{sin(23\°)}[/tex]  

Finally:

[tex]n_{1}=1.57[/tex]