425 mL of neon gas at -12°C and 788 mmHg
expands into a 2.40 L container while the
pressure decreases to 577 mmHg. What is the
temperature of the gas in °C?
Enter the answer

Respuesta :

Answer:

The final temperature is 806.226 degrees celcius.

Explanation:

It is given that initial conditions are as follows,

Initial volume = [tex]425 ml[/tex]

Initial temperature =[tex]- 12 degrees celcius = 261 K[/tex]

Initial pressure =[tex]788 mmHg[/tex]

The final conditions are as follows,

Final volume = [tex]2.4 liters[/tex]

Final pressure = [tex]577 mmHg[/tex]

Final temperature = "T"

Let R be universal gas constant, n be number of moles..

The ideal gas equation, is as follows,

[tex](pressure)(volume) = (number of moles)(R)(temperature)[/tex]

The number of moles remain constant in the process,

so equating initial number of moles = final number of moles , we get

[tex]\frac{(788)(425)(10^{-3}}{261} = \frac{(577)(2.4)}{T}[/tex]

[tex]T = 1079.226 K[/tex] = 806.226 degrees celcius