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Solve using long division.
(3x^2+7x-20) / (x+4)

please show work on paper pls, it'll be more helpful

Respuesta :

Answer:

Quotient is [tex]3x-5[/tex] and remainder is 0.

Step-by-step explanation:

Given:

Dividend = [tex]3x^2+7x-20[/tex]

Divisor = [tex]x+4[/tex]

The long division is shown in the attachment.

Step 1: we need to divide [tex]3x^2+7x-20[/tex] with [tex]x+4[/tex] we first multiply [tex]x+4[/tex] with 3x we get the remainder as [tex]-5x-20[/tex]

Quotient as 3x.

Step 2: Now the dividend is [tex]-5x-20[/tex] and divisor [tex]x+4[/tex] now we will multiply [tex]x+4[/tex] with -5 we get the remainder as 0 and Quotient as [tex]3x-5[/tex]

Hence Quotient is [tex]3x-5[/tex] and remainder is 0.

Ver imagen jitumahi76