Answer:
[tex]y = (\frac{8}{-3})(x) - 16[/tex]
Step-by-step explanation:
The given points are (-6,5) and (-3,-3)
The equation of the line is of the form,
[tex](y-y1) = m(x-x1)[/tex] , m is the slope of line and (x1,y1) is one of the end points.
The slope m of the line is calculated as,
[tex]\frac{(y2)-(y1)}{(x2)-(x1)} = \frac{(5)-(-3)}{(-6)-(-3)} = \frac{8}{-3}[/tex]
Thus the line equation is,
[tex](y-5) = (\frac{8}{-3})(x-(-6))[/tex]
[tex]y = (\frac{8}{-3})(x-(-6)) + 5[/tex]
[tex]y = (\frac{8}{-3})(x) - 16[/tex]
