Answer:
53.3 g C6H6
Explanation:
C₆H₆(l) → 3 C₂H₂(g) ∆H= 630 kj
From reaction 1 mol ∆H= 630 kj
Given x mol ∆H= 430 kj
x = (1 mol*430 kJ)/630 kJ = 0.683 mol C6H6
M(C6H6) = 12*6 + 1*6= 78 g/mol
0.683 mol C6H6 * 78 g/mol ≈ 53.3 g
53.24 g of C₆H₆ will decompose to transfer 430 KJ of heat energy
The balanced equation for the reaction is given below:
Next, we shall determine the mass of C₆H₆ that decomposed to transfer 630 KJ of heat energy.
Molar mass of C₆H₆ = (12×6) + (1×6)
= 72 + 6
= 78 g/mol
Mass of C₆H₆ from the balanced equation = 1 × 78 = 78 g
Thus,
From the balanced equation above,
78 g of C₆H₆ decomposed to transfer 630 KJ of heat energy.
Finally, we shall determine the mass of C₆H₆ that will decompose to transfer 430 KJ of heat energy.
From the balanced equation above,
78 g of C₆H₆ decomposed to transfer 630 KJ of heat energy.
Therefore,
X g of C₆H₆ will decompose to transfer 430 KJ of heat energy i.e
X g of C₆H₆ = [tex]\frac{78 * 430}{630}\\\\[/tex]
Thus, 53.24 g of C₆H₆ will decompose to transfer 430 KJ of heat energy
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