For this case we have that by definition, the line equation of the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut-off point with the y axis
According to the statement we have:
[tex]m = \frac {1} {2}[/tex]
Thus, the equation is of the form:
[tex]y = \frac {1} {2} x + b[/tex]
We substitute the given point and find "b":
[tex]-4 = \frac {1} {2} (1) + b\\-4 = \frac {1} {2} + b\\-4- \frac {1} {2} = b\\b = - \frac {9} {2}[/tex]
Finally, the equation is of the form:
[tex]y = \frac {1} {2} x- \frac {9} {2}[/tex]
Answer:
[tex]y = \frac {1} {2} x- \frac {9} {2}[/tex]
