Answer:
72·45 °C
Explanation:
Given
Mass of sample of aluminum is 500·0 g
Initial temperature is 25·0 °C = 298 K
Heat absorbed from surroundings is 32·60 kJ
Heat capacity of aluminum is 0·9 J/g K
Formula for amount of heat transfer is
where
Q is the amount of heat transfer
m is the mass of the substance
s is the heat capacity of the substance
ΔT is the change in temperature
Let the final temperature be T K
∴ 32·60 × 1000 = 500 × 0·9 × (T - 298)
T - 298 = 72·45
∴ T = 370·45 K = (370·45 - 298) °C = 72·45 °C
∴ Final temperature is 72·45 °C
