Answer:
Ans A). The graph is shown.
Ans B). 18.3333 C temperature when F is 65 temperature
Ans C). 32 F when the line crosses the horizontal axis
Ans D). Slope of line C=[tex]\frac{5}{9}(F -32)[/tex] is [tex]\frac{5}{9}[/tex]
Step-by-step explanation:
Given equation is C=[tex]\frac{5}{9}(F -32)[/tex]
Ans A).
For the table,
Take the four value of F as 32,41,50,59.
For F = 32.
The value of C is
C=[tex]\frac{5}{9}(F -32)[/tex]
C=[tex]\frac{5}{9}(32 -32)[/tex]
C=0.
For F = 41.
The value of C is
C=[tex]\frac{5}{9}(F -32)[/tex]
C=[tex]\frac{5}{9}(41 -32)[/tex]
C=05
For F = 50.
The value of C is
C=[tex]\frac{5}{9}(F -32)[/tex]
C=[tex]\frac{5}{9}(50 -32)[/tex]
C=10
For F = 59.
The value of C is
C=[tex]\frac{5}{9}(F -32)[/tex]
C=[tex]\frac{5}{9}(32 -32)[/tex]
C=15
Note: The figure shows a graph of given equation with points.
Ans B). Estimate temperature in C when the temperature in F is 65
For F = 65.
The value of C is
C=[tex]\frac{5}{9}(F -32)[/tex]
C=[tex]\frac{5}{9}(32 -32)[/tex]
C=18.333333.
Ans C). At what temperature, graph lien cross the horizontal axis
When the line crosses the horizontal axis, C=0
Therefore,
C=[tex]\frac{5}{9}(F -32)[/tex]
0=[tex]\frac{5}{9}(F -32)[/tex]
0=[tex](F -32)[/tex]
F=32 Temperature.
Ans D). Slope of the line C=[tex]\frac{5}{9}(F -32)[/tex]
The slope of line is given by s= [tex]\frac{Y1-Y2}{X1-X2}[/tex]
Take points from the table of answer A.
let (32,0) and (41,5) using for slope.
s= [tex]\frac{Y1-Y2}{X1-X2}[/tex]
s= [tex]\frac{0-5}{32-41}[/tex]
s= [tex]\frac{5}{9}[/tex]
Slope of line C=[tex]\frac{5}{9}(F -32)[/tex] is [tex]\frac{5}{9}[/tex]
