Answer:
The ratio of the amount for swordfish to the amount of salmon is 6:4
Step-by-step explanation:
Given as :
The price for 1 pound of swordfish = The price of 1.5 pound of salmon
So, On this relation
The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 ) pound of salmon
i.e The price for 2 pound of swordfish = The price of 3 pound of salmon
Now According to question
Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39
Let the money she pay for swordfish = 2 sw
And The money she pay for salmon = 3 sa
∵, The total money she pay for both = $ 39
I.e 2 sw + 3 sa = 39
As 2 sw = 3 sa
So, 3 sa + 3 sa = 39
Or, 6 sa = 39
or, sa = [tex]\frac{39}{6}[/tex] = [tex]\frac{13}{2}[/tex]
∴ sw = [tex]\frac{13}{2}[/tex] × [tex]\frac{3}{2}[/tex]
or, sw = [tex]\frac{39}{4}[/tex]
Now, the ratio of the amount for swordfish to the amount of salmon = [tex]\frac{\frac{39}{4}}{\frac{13}{2}}[/tex]
I.e The ratio = [tex]\frac{6}{4}[/tex]
Hence The ratio of the amount for swordfish to the amount of salmon is 6:4
Answer