Components of the velocity and of the acceleration in the projectile motion:
[tex]a_x = 0\\a_y=-g m/s^2[/tex]
[tex]v_x = u cos \theta\\v_y = u sin \theta - gt[/tex]
Explanation:
The motion of a projectile consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction
Therefore we have the following:
Acceleration:
- Along the horizontal direction, the acceleration is zero, since there are no forces acting in this direction: [tex]a_x=0[/tex]
- Along the vertical direction, the acceleration is equal to the acceleration of gravity, acting downward: [tex]a_y = -g = -9.8 m/s^2[/tex]
Velocity:
- Along the horizontal direction, the velocity is constant, since there is no acceleration, so it is [tex]v_x = u cos \theta[/tex], where u is the initial speed and [tex]\theta[/tex] is the angle of projection of the projectile
- Along the vertical direction, the velocity is given by the suvat equation [tex]v_y = u_y + a_yt[/tex], where
[tex]u_y = u sin \theta[/tex] is the vertical component of the initial velocity
[tex]a_y = -g= -9.8 m/s^2[/tex] is the acceleration of gravity
So, we have
[tex]v_y = u sin \theta - g t[/tex]
Learn more about projectile motion:
brainly.com/question/8751410
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