The stone will be moving with an acceleration of 9.8 m/s² and its velocity when it reaches the ground will be 29.7 m/s in downward direction.
Explanation:
We will use the equations of motion to solve this problem.
First let us get familiar with the situation.
The initial velocity (u) of the stone is zero when it is dropped. Considering the frictional force negligible the only force that is acting upon the stone is the gravitational force that produces an acceleration (a) of 9.8 m/s².
We need to find the final velocity (v) when it reaches the ground.
Height = h = 45 m
Using the third equation of motion; 2gh = v² - u²
⇒ 2*9.8*45 = v² - 0²
⇒ v² = 882
Taking Square root on both sides:
⇒ v = √882
v = 29.69
v = 29.7 m/s
Hence, the final velocity when the object reaches the ground is 29.7 m/s in downward direction.
Keywords: Equation of Motion, Linear Motion, Vertically downward motion
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