Answer: 1018.26 m/s
Explanation:
Approaching the orbit of the Moon around the Earth to a circular orbit (or circular path), we can use the equation of the speed of an object with uniform circular motion:
[tex]V=\sqrt{G\frac{M}{r}}[/tex]
Where:
[tex]V[/tex] is the speed of travel of the Moon around the Earth
[tex]G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}[/tex] is the Gravitational Constant
[tex]M=5.972(10)^{24} kg[/tex] is the mass of the Earth
[tex]r=384400(10)^{3} m[/tex] is the distance from the center of the Earth to the center of the Moon
Solving:
[tex]V=\sqrt{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{5.972(10)^{24} kg}{384400(10)^{3} m}}[/tex]
[tex]V=1018.26 m/s[/tex] This is the speed of travel of the Moon around the Earth
