Answer:
[tex]\frac{\textbf{dy}}{\textbf{dx}} = \textbf{10ax}+\textbf{9bx}^2[/tex]
Step-by-step explanation:
Let
[tex] y= 5ax^2+3bx^3+5 [/tex]
Differentiating y with respect to x
[tex] \frac{dy}{dx} =5a(2x)+3b(3x^2)+0[/tex]
[tex]\frac{dy}{dx}= 10ax+9bx^2[/tex] where a and b are constants
