Answer:
The recommended way of preparing 100ml of 0.02 M from 2M NaOH in the laboratory is to obey the equation V1S1=V2S2.
Explanation:
According to the given question
V2=100ml
S2=0.02M
S1= 2M
Then V1=?
We all know that V1S1=V2S2
or V1=V2×S2÷S1
or V1= 100×0.02÷2
or V1 =1 ml
It can be concluded that 1ml of 2M NaOH solution and 99 ml distilled water should be mixed to prepare 100ml of 0.02 M NaOH solution.
