Answer:
3 [tex]\frac{9}{10}[/tex]
Step-by-step explanation:
Note that + (- ) = -
Given
6 [tex]\frac{1}{5}[/tex] + ( - 2 [tex]\frac{3}{10}[/tex])
= 6 [tex]\frac{1}{5}[/tex] - 2 [tex]\frac{3}{10}[/tex]
Change both mixed numbers into improper fractions, that is
= [tex]\frac{31}{5}[/tex] - [tex]\frac{23}{10}[/tex]
We require both denominators to be common before subtracting.
Multiply the numerator/ denominator of the first fraction by 2
= [tex]\frac{31(2)}{5(2)}[/tex] - [tex]\frac{23}{10}[/tex]
= [tex]\frac{62}{10}[/tex] - [tex]\frac{23}{10}[/tex]
Now subtract numerators leaving the denominator
= [tex]\frac{62-23}{10}[/tex]
= [tex]\frac{39}{10}[/tex] ← change back to a mixed number
= 3 [tex]\frac{9}{10}[/tex]
