Answer:
0.00049 m³
3328.54854 kg/m³
Explanation:
W = Weight of ore = 16 N
T = Tension of cord = 11.4 N
B = Buoyant force
g = Acceleration due to gravity = 9.81 m/s²
[tex]\rho_w[/tex] = Density of water = 1000 kg/m³
As all the forces are conserved
[tex]T+B-W=0\\\Rightarrow B=W-T\\\Rightarrow B=16-11.4\\\Rightarrow B=4.9\ N[/tex]
Volume is given by
[tex]v=\dfrac{B}{\rho_w g}\\\Rightarrow v=\dfrac{4.9}{1000\times 9.81}\\\Rightarrow v=0.00049\ m^3[/tex]
The volume of the sample is 0.00049 m³
Density is given by
[tex]\rho=\dfrac{m}{v}\\\Rightarrow \rho=\dfrac{W}{gv}\\\Rightarrow \rho=\dfrac{16}{9.81\times 0.00049}\\\Rightarrow \rho=3328.54854\ kg/m^3[/tex]
The density is 3328.54854 kg/m³
